Answers
 1. 3: 3 is the median, , of 2 and 4. It exactly in the middle of 2 and 4.

 2. 2: there is no other number between the two 2s

 3. 3: 3 is the median, , of 1 and 5. It exactly in the middle of 1 and 5.
 Notice that 3 is the median of 12345. Three is the mean of 1 and 5, the mean must be used because there are only 2 numbers.
(1+5)/2 = 3

 4. 3: order the numbers 1, 5 1*3*5, 3 is in the middle, the median position;
 (1+5)/2 = 3: the median, , is 3, is also the mean, , of 1 and 5

 5. 3: because 3 , 7, 2 is 3 numbers the median is easy to find. Order the numbers, 2, 3, 7 ,
is 3

 6. 2: 0, 4, 0, 4, 0,0,4,4, is the mean of the middle 0 and 4 is 2

 7. 4: 1, 3, 5, 4, 2, 6, 5 1, 2, 3, 4, 5, 5, 6.
 There are an odd number of data points, the median is visible in the ordered middle position.
 The median is 4.

 8. 3.5: 1, 3, 5, 4, 3, 2, 6, 5 1, 2, 3, 3, 4, 5, 5, 6, the median is 3.5 the mean of 3 and 4

 9. 3: 3 occurs most

 10. 5, 7: 5 and 7 have the highest and equal frequencies, they are each considered modes.
 It is a special case. The sample is said to be bimodal, having 2 modes.

 11. There is no mode because each data point occurs with the same frequency.

 12. 4.5: (2+4+5+7)/4 = 18/4 = 4.5

 13. 2: (1+2+3)/3 = 6/3 =2. Notice, the mean is also the median.

 14. 79%: (100+90+50+75+80)/5 = 395/5 = 79%

 15.

 16. 3.5: 2 is the lo. 5 is the hi. (2+5)/2 = 3.5 Notice it is close to the median which is 4
 and the mean which is 3 2/3.

 17.

 18. There are 9 data points in the sample. The mean is 8, the mode is 12, the median is 7, and the midrange is 10.5.
The scores range from a low of 1 to a high of 20. The mode has a frequency of 2.
 One might also add: "The data points are:
1, 2, 4, 5, 7, 9, 12, 12, and 20," but this is not usually included.
