Techniques of Algebra Work With Functions
Recall the following from algebra I and see how these laws create new functions.
- (xa)(xb) = xa+b -- to multiply, add exponents
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- xa ÷ xb = xa-b -- to divide, subtract exponents
Multiplication produces these new functions.
- (constant)(constant) = (constant)
Ex. (5)(2) = 10
- (constant)(line) = (line)
Ex. (5)(2x+3) = 10x+15
- (line)(line) = (quadratic)
Ex. (5x)(-x+3) = -5x²+15x
- (line)(quadratic) = (cubic)
Ex. (5x)(x²+3x+1) = -5x3+15x2+5x
- (3rd degree function)(5th degree function) =
(8th degree equation)
Ex. (5x3)(2x5) = 10x8
Division produces these new functions.
- (constant)/(constant) = (constant)
Ex. (5)/(2) = 2.5
- (constant)/(line) = (reciprocal function) , also a rational function
Ex. (5)/(2x+3) = (5)/(2x+3)
- (line)/(line) = (reciprocal function), also a rational function
Ex. (5x)/(-x+3) = 15/(-x+3) - 5
- (line)(quadratic) = (rational function)
Ex. (5x)/(x²+3x+1)
- (quadratic)/(line) = (rational function)
Ex. (x²+3x+1)/(5x)
- (3rd degree function)/(5th degree function) =
(rational function)
Ex. (5x3)/(2x5) = 5/2x2
When using multiplication to compose a function,
- a zero of a factor is a zero of the composed product function.
- a restriction in a factor is a restriction of the composed product function.
When using division to compose a function,
- almost always, a zero of the numerator is a zero of the composed rational function.
- almost always, a zero of the numerator creates a vertical asymptote of the rational function.
- if the same zero exists in a numerator factor and a denominator factor, a discontinuity
(a hole in the function) is created.
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