3/7
- I. In the book, pg 177, #40, 42, 46, 52
- II. Given:
- width = x
- length= one less than double the width
- height = 6 cm
- Write volume function
- Write surface area function  Go to Answers
- II. Write the distance function if:
-     The initial distance is 10 cm and the object travels 25 cm/sec.
-
-     At the start, time zero, t0, the distance is 10.
The "y-intercept" is 10.
-     The object travels 25 cm/sec. so after 1 second, the object has
traveled 25 cm so the slope is 25/1 or 25.
-     The equation is linear. It is d(t) = 25x + 10.
3/9
- I. Please do: pg 189 # 67, 68 then
- II. Write the area formula given:
-   Answer
- III. Solve algebraically:
- 1.)     x + 2 = 0  
- 2.)     x + 2 = - x + 3  
- 3.)     x² - 5x - 14 = 0  
-  
- IV. Solve x + 2 = - x + 3 graphically:
-   When the two curves cross, they are equal.
The x-value of this ordered pair is the solution to the equation.
- V. Solve on the calculator using the CALC (83) or MATH (85, 86) menu.
- 85:
- 1st: In [GRAPH] in y(x)= enter each expression as a function.
- 2nd: Press [EXIT] then [MORE] to find the [MATH] menu.
- 3rd: Press [MATH] then [MORE] then [ISECT] for intersect.
- 4th: On the graph, move the curser till the spider is sitting on one function.
- 5th: Press [ENTER]
- 6th: Move the curser/spider to the other function.
- 7th: Press [ENTER] to solve.
   
-  
- 83:
- 1st: In y= enter each expression as a function.
- 2nd: Press [CALC] for calculus (above [TRACE]).
- 3rd: Press
-     Also enter the variable, x, and
-     a constant or seed value or guess to start the computation.
- 4th: Press [ENTER] to solve.
-  
- VI. Solve on the calculator using SOLVER (82, 83) or SOLVE (85, 86).
- 85:
- 1st: Press SOLVER (above GRAPH)
- 2nd: Enter the equation
-     Ex. equ:leftside = rightside
-     Ex. equ:x + 2 = - x + 3 (The = is above [STO>].
- 3rd: Press [ENTER]
- 4th: Be sure the curser is on the line with the varible you want.
- 5th: On the soft keypad, press [SOLVE].
-  
- 82:
- 1st: Rewrite the equations so one side or member is 0.
- 2nd: Press [MATH] then [0:Solver(]
- 3rd: Enter the expression in step 1 as part of the
argument of the Solver function.
-     Also enter the variable, x, and
-     a constant or seed value or guess to start the computation.
-     Ex. Solve(expression, variable, seed
-     Ex. Solve(x + 2 + x - 3, x, 5
- 4th: Press [ENTER] to solve.
- 83:
- 1st: Rewrite the equations so one side or member is 0.
- 2nd: Press [MATH] then [0:Solver(]
- 3rd: Press the curser to get up to the equation line.
- 4th: Type the expression from step 1 after the =.
- 5th: Press the curser down to the line with the variable you wish to find.
- 6th: Press [SOLVE] ([ALPHA][ENTER]) to solve.
-  
- VII. Solve on the calculator using POLY (85, 86).
- 85:
- 1st: Press POLY (above PRGM)
- 2nd: Enter order 2 for 2nd degree, 3 for 3rd degree, ...
- 3rd: Enter each coefficient as pictured in the equation.
- 4th: On the soft keypad, press [SOLVE].
-  
- VIII. Solve algebraically.
- 1.)     x + 5 = 5 + x  
- 2.)     x + 5 = 6  
- 3.)     x + 5 = 7 + x  
-  
- IX. Homework: ch 2.1 and 2.2.
3/14
- I. Without looking at your notes, state the
quadratic formula.
- II. Solve example problems in chapter 2 section 4 and solve:
- x2 + 1 = 0
- III. Vocabulary: 
discriminant 
real number 
rational number
- IV. Calculator Computation Technique
-     The [ENTRY] or [2ND][ENTER] key is used to recall the last entry so that
it may be edited and a similar computation completed w/ few keystrokes.
- Ex. Solve x2 + 8x + 12 using the quadratic formula.
- 1st:   Type (-8+
(((8)2-4(1)(12)))/(2*(1)) and [ENTER]
- 2nd: The result is -2
- 3rd: Press [ENTRY] or [2ND][ENTER].
- 4th: Use the curser to move & type over the + sign.
-     (-8-
(((8)2-4(1)(12)))/(2*(1))
- 5th: Press [ENTER] to obtain the other root.
- 6th: The result is -6.
3/16
- I. In the book, pg 212 #36, 53, 59
- II. Sketch
- 1. y = |x+3|-2
- 2. y = |x-6|
- III. Solve
- 3. |x+3|-2 = |x-6|
- IV. Expand
- 4. (x+3)2
- 5. (x + a)2
- 6. (2 - x)2
- 7.
(x + 2)2
- V. Solve
- 8.
(2x + 7) - x = 2
- 8. x4 - 1 = 0
    Answer
- VI. Vocabulary
- Look for extraneous roots -- answers which solve the final
equation but not the original equation.
|