5c. There are 12 coins in a bank and the
coins have a value of $1.20.
The are five more dimes than nickels and all the rest of the coins are quarters.
Find how many dimes are in the bank.
- (nickels) + (dimes) + (quarters) = 12
-
- (total value) = $1.20
-
- .05(nickels) + .10(dimes) + .25(quarters) = $1.20
-
- 5(nickels) + 10(five more than nickels) + 25(quarters) = 120
-
- 5(x) + 10(5 + x) + 25(quarters) = 120
-
- 5(x) + 10(5 + x) + 25(the rest of the 12 coins) = 120
-
- 5(x) + 10(5 + x) + 25(12 - (x + 5 + x)) = 120
- 5(x) + 10(5 + x) + 25(12 - 2x - 5) = 120
- 5x + 50 + 10x + 25(12 - 2x - 5) = 120
- 15x + 50 + 25(7 - 2x) = 120
- 15x + 50 + 175 - 50x = 120
- -35x + 225 = 120
- -35x = -105
- x=3
-
- x=3, and x + 5 = 8, and 12 -(x + 5 + x) = 1
- The are 3 nickels, 8 dimes, and one quarter.
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