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Oscar Reutersvard's Penrose Square -- Solve the quadratic.
Connect the answers in order, perhaps w/a straightedge.
Start a new line.
1. x² - 8x + 16 = 0
2. (x + 1)(x + 2) = 0
3. x² - 7x +12 = 0
Start a new line.
4. x² + 3x = - 2
5. (x - 2)(x - 4) = 0
Start a new line.
6. x² + 1x - 6 = 0
7. x² - 3x - 10 = 0
8. x² - 6x + 9 = 0
9. x² = 6x - 8
10. x² + x = 6
11. (x - 6)² = 0
12. x² + 5x + 9 = - x
13. x² + 1 = - 2x
14. x² + 8x + 16 = 0
15. x² + 14x + 49 = 0
16. x² - 6x + 5 = 0
17. x² + 7x + 10 = 0
18. x² - x - 6 = 0
Start a new line.
19. x² - 3x - 4 = 0
20. x² + x - 20 = 0
21. x² - 18x + 81 = 0
22. x² - 10x + 24 = 0
23. x² + 12x + 36 = 0
24. (x + 5)² = 0
25. x² - 8x + 15 = 0
26. x² + 16x + 64 = 0
27. x(x + 1) = 0
28. x² - 5x + 6 = 0
29. x² - 4x + 4 = 0
30. x² - 6x + 9 = 0
Start a new line.
31. x² + 10x + 25 = 0
32. - x² + 5x - 6 = 0
33. x² - 5x = 0
34. x² = 0
35. x² - 8x + 16 = 0
36. x(x-1)(x-2) = 0
37. x² - 3x - 10 = 0
Start a new line.
38. x³ -3x² +2x = 0
39. 12 + x² = 7x
40. x² - 2x + 1 = 0
41. (x - 8)² = 0
42. x² - 10x + 5 = - 20
43. x² + 4x + 4 = 0
44. x² - 7x + 6 = 0
45. x² - 5x - 6 = 0
46. x² + 7x + 12 = 0
47. x² + 7x + 6 = 0